Q) Simplify : .cos^(βˆ’1) ((sinπ‘₯+cosπ‘₯)/√2),πœ‹/4=π‘₯=5πœ‹/4 #shivangmathsacademy #maths #cbsemaths
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Q) Simplify : .cos^(βˆ’1) ((sinπ‘₯+cosπ‘₯)/√2),πœ‹/4=π‘₯=5πœ‹/4 #shivangmathsacademy #maths #cbsemaths
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Q) Simplest form of tan^(βˆ’1) ((√(1+cosx)+√(1βˆ’cosx))/(√(1+cosx)βˆ’βˆš(1βˆ’cosx))), Ο€=x=3Ο€/2 is#class
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Q) Simplest form of tan^(βˆ’1) ((√(1+cosx)+√(1βˆ’cosx))/(√(1+cosx)βˆ’βˆš(1βˆ’cosx))), Ο€=x=3Ο€/2 is#class
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Q) Simplify :sin^(βˆ’1) (5/13 cosπ‘₯+12/13 sinπ‘₯)#class12maths #shivangmathsacademy #cbsemaths
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Q) Simplify : tan^(βˆ’1) ((cos2π‘₯βˆ’sin2π‘₯)/(cos2π‘₯+sin2π‘₯)),0=π‘₯=πœ‹/4..#class12maths #shivangmathsaca
1:58
Q) Simplify : tan^(βˆ’1) ((cos2π‘₯βˆ’sin2π‘₯)/(cos2π‘₯+sin2π‘₯)),0=π‘₯=πœ‹/4..#class12maths #shivangmathsaca
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Q) Find the domain of 𝑝(π‘₯)=sin^(βˆ’1) (1βˆ’2π‘₯^2 ). Hence,find the value of π‘₯ for which p(π‘₯)=πœ‹/6.
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Q) Find the domain of 𝑝(π‘₯)=sin^(βˆ’1) (1βˆ’2π‘₯^2 ). Hence,find the value of π‘₯ for which p(π‘₯)=πœ‹/6.
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Q) The following graph represents (A) 𝑦=cos^(βˆ’1) π‘₯ (B) 𝑦=sec^(βˆ’1) π‘₯ (C) 𝑦=sin^(βˆ’1) π‘₯ (D)
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Q) The following graph represents (A) 𝑦=cos^(βˆ’1) π‘₯ (B) 𝑦=sec^(βˆ’1) π‘₯ (C) 𝑦=sin^(βˆ’1) π‘₯ (D)
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If 𝑦=𝑠𝑖𝑛^(βˆ’1) π‘₯,βˆ’1≀π‘₯≀0,then the range of 𝑦 is(A) ((βˆ’πœ‹)/2,0)(B) [(βˆ’πœ‹)/2,0](C) [(βˆ’πœ‹)/2,0
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Q) The graph of a trigonometric function is as shown. Which of the following will represent graph of
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Q) The domain of 𝑓(π‘₯)=cos^(βˆ’1) (2π‘₯βˆ’5) is #shivangmathsacademy #inversetrigonometry #cbsemaths
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Q) Evaluate :tan^(βˆ’1) (βˆ’1/√3)+cot^(βˆ’1) (1/√3)+tan^(βˆ’1) (sin(βˆ’πœ‹/2))+tan^(βˆ’1) (tan 2πœ‹/3)
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Q) For the inverse trigonometric functions, which of the following Principal Value Branch
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If π‘π‘œπ‘‘^(βˆ’1)(3x + 5) = πœ‹/4 then find the range of the values of x #shivangmathsacademy #maths
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